Miami Dolphins linebacker Jordyn Brooks has been named AFC Defensive Player of the Week for his performance in Sunday's game at Atlanta, the NFL announced Wednesday.
It is the first AFC Defensive Player of the Week honor of his career and Miami's first AFC Defensive Player of the Week selection since linebacker Tyrel Dodson earned the accolade in Week 17 of the 2024 season at Cleveland.
Brooks led the team with 10 tackles (seven solo), 1.0 sack and three tackles for loss in Miami's 34-10 victory over the Falcons.
He recorded six (five solo) of his 10 tackles, the sack and the three tackles for loss in the first half, becoming the only NFL player this year to record such stat line in a single half and the first Dolphins player to do so since Ndamukong Suh against Philadelphia in 2015.
Brooks's performance helped the Dolphins defense limit the Falcons fourth-ranked rushing attack to 45 rushing yards, the fewest allowed by Miami since limiting the N.Y. Jets to 23 in 2023. In the first half alone, Miami yielded only 10 rushing yards, 58 total yards, and did not allow a third down conversion on five attempts.
Brooks, who was named to his first-career team captaincy this year after signing with Miami as an unrestricted free agent in 2024, leads the NFL with 85 tackles (53 solo) entering Week 9. He has also tallied one fumble recovery and 2.5 sacks this year and is the only player in the NFL to have recorded 80-plus tackles, a fumble recovery and multiple sacks in each of the last two seasons.
